4m^2+1m-10=0

Solution for 4m^2+1m-10=0 equation:

4m^2+1m-10=0

We add all the numbers together, and all the variables

4m^2+m-10=0

a = 4; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·4·(-10)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{161}}{2*4}=\frac{-1-\sqrt{161}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{161}}{2*4}=\frac{-1+\sqrt{161}}{8}
$